How many moles of nickel(II) chloride are needed to produce 0.515 mol nickel(II) phosphate?

using stoichiometry, we know that there are 3 moles of NiCl2 needed to from 1m0le of Ni3(PO4)2..thus, 0.515 mol Ni3(PO4) was produce by reacting 1.545 moles of NiCl2...this is because the ratio is 3:1.